In an examination, 34% of the students failed in mathematics and 42% failed in English. If 20% of the students failed in both the subjects, Then Find the Percentage of Students who passed in both the subjects? 

In an examination, 34% of the students failed in mathematics and 42% failed in English. If 20% of the students failed in both the subjects, Then Find the Percentage of Students who passed in both the subjects?

The percentage of students who passed in both mathematics and English is 44%.

Let's denote:

• A = Students who failed in mathematics
• B = Students who failed in English
• C = Students who failed in both subjects

Given:

A = 34%

B = 42%

C = 20%

Percentage of students who failed in at least one subject =

A + B - C = 34% + 42% - 20%

= 76% - 20%

= 56%

Percentage of students who passed in both subjects = 100 % - Percentage of students who failed in at least one subject

= 100% - 56% = 44%

So, the percentage of students who passed in both mathematics and English is 44%.

Example Problems to Work out

1. In a class of 80 students, 25% failed in Science and 30% failed in History. If 10% failed in both subjects, find the percentage of students who passed in both subjects.

2. Out of 120 employees in a company, 40% failed in the sales department and 35% failed in the marketing department. If 15% failed in both departments, find the percentage of employees who passed in both departments.

3. In a survey of 200 people, 60% reported that they do not exercise regularly and 45% reported that they do not eat a balanced diet. If 20% reported that they neither exercise regularly nor eat a balanced diet, find the percentage of people who reported that they do both.

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